Thread: (1/2)y'' + y^2 = 1 View Single Post
 Well darn. I went back and checked my derivation of the d.e. and realized I had a minus sign wrong. The correct equation is (I pretty sure this time ), $$\frac{1}{2}y'' + 2y^{\frac{1}{2}}y' + y^2 = 1$$ So I guess I'll get to work on this one...