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May12-08, 08:43 PM
P: 100
Well darn. I went back and checked my derivation of the d.e. and realized I had a minus sign wrong. The correct equation is (I pretty sure this time ),

[tex]\frac{1}{2}y'' + 2y^{\frac{1}{2}}y' + y^2 = 1[/tex]

So I guess I'll get to work on this one...