First of all, I'd like to thank you for your quick reply. However, I'm not quite sure if I understand you correctly.
Ok, so the battery's emf is 6V, internal resistance is 0.6 Ohms, and the circuit's net resistance is 7.20 Ohms.
When you said:
I took that as...the total circuit has a resistance of 7.8 Ohms.
So, I have a current of 6.0/7.8 = 0.769 Amps ??
So...I found that as Current X Internal Resistance = 0.462 V
6.0 V - 0.462 V = 5.54 V, which is the answer.
So...I don't need to worry about the resistance through the circuit?