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:
equation x^2+y^2+z^2=1
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lstellyl
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10
Oct12-09, 06:16 PM
P: 41
NO, here you have x=y=-z and x^2+y^2-z^2=1 which leads to 2x^2-x^2=1 and thus x=1,x=-1. HOWEVER, notice that this is in the case that x,y,z<>0.