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 Quote by naspek 1. The problem statement, all variables and given/known data The period T of a simple pendulum with small oscillations is calculated from the formula T = 2pie (L / g)^1/2 . Suppose that measurements of L and g have errors of at most 0.5% and 0.1% respectively. Use differentials to approximate the maximum percentage error in the calculated value of T. 3. The attempt at a solution dT = (dT/dL)dL + (dT/dg)dg = 2pie (1/2g(L/g)^1/2) dL + 2pie (1/2g(L/g^2)^1/2) dg i dont know how am i going to proceed..
You're not using the chain rule correctly. Also, the name of the Greek letter is pi, not pie.
dT/dt = d/dt(2 pi sqrt(L/g)) = 2 pi d/dt( L^(1/2)/g^(1/2))
Now use the quotient rule to complete the differentiation on the right. After you get that, you can multiply both sides of your equation by dt to get an equation that involves dT, dL, and dg.