Thread: Simple inertia
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a.mlw.walker
#1
Feb15-10, 05:38 AM
P: 153
So I have a piston connected to a flywheel. If i push the piston with a force F, how does the equation of motion look? I'm not confident about putting inertias into the same equation as accelerations?

F = ma

F = I(theta'')

The force is changing with time.

EDIT:

So i have just realised that T = Ia, a is angular acceleration.

So if i find resultant force of piston acting along line of tangential velocity on the flywheel, then moultiply it by r of the flywheel,

Fr = Ia, then rearrange for a and i have angular acceleration of flywheel?
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