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Dickfore
#11
Aug19-10, 03:21 PM
P: 3,014
Quote Quote by fatimajan View Post
Hi, Dickfore
Thank you very much for your help again. you've introduced a new p, If I understand correctly, that is:
u^(1/2)*p~p
but didn't you mean, u^(-1/2)*p~p? ( Actually I mentioned the power of u)
Yes. You are right. However, everything else is correct (I made p -> u^{1/2} p as it should be in the continuation of that line).