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sooperdrave
#9
Sep9-10, 12:43 AM
P: 8
Quote Quote by cepheid View Post
0.13% = 0.0013

This is the ratio of output power to input power:

P_out / P_in = 0.0013

Hence, P_in = P_out / 0.0013

This result makes sense since it means the input power is much greater than the output power (due to the inefficiency in the supply). Once you have P_in, you can just do the same calculations as before. I was hoping that you would write these equations down and work it out for yourself. They are nothing more than the mathematical version of what I said in post #5 using words.
i actually did write them out...but i used multiplication instead of division. this is only my second week of class, and i have been out of school for a decade. i know this question probably isnt a hard one, but its 1:43am here and my brain hurts from 4 hours of homework. i really do appreciate the help!