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Oct8-10, 10:26 PM
P: 6
Nevermind, I figured out how to solve the problem using my old differential equations textbook. In case someone is curious, here's what I did:

I rearranged the terms so that like terms were on the same side:


I then integrated each side:

[tex]\int -\frac{1}{z_{1}^{2}}dz=\int dt[/tex]

Since both sides had constants, I dropped one, and I then used the initial condition of [tex]z_{1}(t=0)=x_{1}[/tex] to solve for C


I plugged in C above and got this equation for Lagrangian position: