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A is a root of order of polynomial p iff p(a)=p'(a)=...=[p^(k-1)](a)=0
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lanedance
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2
Nov28-10, 05:52 AM
HW Helper
P: 3,307
how about starting from below & differentiating k times
[tex] p(x)=(x-a)^k r(x) [/tex]