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What does it mean by a Riemannian metric on a vector bundle?
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petergreat
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8
Mar18-11, 06:57 PM
P: 270
Quote by
lavinia
no. There is no natural metric. Why do you think that? Can you give me a proof?
Oops... You're right. But still, does it have to be a
constant
2-tensor on each fiber?