Thread: A recurrence relation View Single Post
HW Helper
P: 3,436

## A recurrence relation

Hmm, after looking at it a bit more I realize it's really not telling us as much as I originally thought.

After solving for gn in

$$g_n=g_{n-1}+\frac{2}{a^2_n-2}g_n$$ to obtain

$$g_n=\frac{a_n^2}{a_n^2-2}g_{n-1}$$

I was simply arguing that the factor approaches 1 as n gets large, but this doesn't really tell us about the limit of gn...