Thread: A recurrence relation View Single Post
 HW Helper P: 3,562 A recurrence relation Hmm, after looking at it a bit more I realize it's really not telling us as much as I originally thought. After solving for gn in $$g_n=g_{n-1}+\frac{2}{a^2_n-2}g_n$$ to obtain $$g_n=\frac{a_n^2}{a_n^2-2}g_{n-1}$$ I was simply arguing that the factor approaches 1 as n gets large, but this doesn't really tell us about the limit of gn...