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Sep17-11, 04:13 AM
P: 169
Ha ha, yeah now i get it :) It's because normally we want to find the potential. But now i get it as the Legendre from 0 to 2, which makes sense by the order of the cartesian polynomial. So i am getting
[itex]\frac{3V_0r^2}{R^2}(3\cos(\theta)^2-1) [/itex]