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Nov22-11, 12:43 PM
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Quote Quote by CRGreathouse View Post
The binary implies the ternary, that's why they're both considered versions of the same problem. But the binary version is much harder.
I'm confused. Suppose the ternary is true. Then, for an even integer, you have that it is the sum of 3 primes. For n>6, one of these must be 2, the other two being odd primes. So then, for every even n>6, the ternary implies n-2 satisfies the binary. Isn't that enough to say that ternary implies binary?