 Quote by CRGreathouse
The binary implies the ternary, that's why they're both considered versions of the same problem. But the binary version is much harder.
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I'm confused. Suppose the ternary is true. Then, for an even integer, you have that it is the sum of 3 primes. For n>6, one of these must be 2, the other two being odd primes. So then, for every even n>6, the ternary implies n-2 satisfies the binary. Isn't that enough to say that ternary implies binary?