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gneill
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#8
Feb15-12, 11:41 AM
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Quote Quote by nbram87 View Post
Curl = d/dx(Fy) i - d/dy (Fx) j
= d/dx [K(x + 2y)] + d/dy [K(2x + y)]
= K(1+ 0) - K (0+1)
= 0
So K - K = 0?
That tells you that the curl is zero no matter what value K has.