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Taiden
#3
Feb22-12, 07:24 AM
P: 9
Hey, thanks for the reply.

You are right. But I didn't draw that in the problem just for simplicity sake. If you break R and T into components, when you sum forces you get:


→ƩFx = 0 = -12/13 T + 4/5 R

Solve for T = 13/15 R

^ƩFy = 0 = +5/13 T + 3/5 R - 180

180 = 14/15 R

R = 192.9 newtons
T = 167.2 newtons



Doing the beginning of the same problem with moments (dont have much time to go through this):

(ccw+) ƩMr = 0 = +T(12/13)(0.36 meters) + T(5/13)(0.48 meters) - 180(0.24 meters)

180(0.24) = 0.517 T
T = 83.57 newtons ????????????????



edit: I just realized when I do moments, the magnitude is half of when I do forces. Any insight?