Quote by stardust006
Find the area of the loop of the curve y^2=x^3(1x)^2 using integral calculus.
The following needs extra parentheses to be correct.
y=(√x^3(1x)^2)
y=√x^3/2 (1x) This should be y = ±√(x^{3}) (1x) or y = ±x^{3/2} (1x) .
To sketch the curve, I assigned values for x and then solved the corresponding values of y.
x= 1, y= 2
x= 0.5, y= 0.53
x=0, y= 0
x= 0.5, y= 0.177
x=1, y=0
how can i find the area of this? >.<

Hello stardust006. Welcome to PF !
The ± is important. It gives a clue as to why the graph has a loop.
There are two xintercepts. Can you find them ?