Nope. Test is 6pm my time, so I'm just tying up a few loose ends.
 Quote by Ansatz7
You've probably already had your test, but everything you have done so far is correct. Now you just need to show that 1 + l(2k + 3) + l2(22k + 4) is congruent to 1 (mod 2k + 3), which it is as far as I can tell...
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How is : 1 + l(2
k + 3) + l
2(2
2k + 4) congruent to 1 (mod 2
k + 3)?
i tried breaking it up: 1 + l(2
k + 3) + l
2(2
k + 2)
2......so it's this last term that's giving me a problem. I also had one other short question if you don't mind?