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 P: 169 So your charge diverges at theta = Pi/2 ? that seems odd to me. If the disc is uniformly charged then the delta function seems to much to me. Can't you use the delta functions most useful prop: $Q(r) = \int_{-\infty}^{\infty} \delta(r-r')Q(r')dr'$ But i think that uniformly means that Q = rho * A (integrate constant)