Thread: Slip systems in HCP metals View Single Post
 P: 667 Oh well.. :-) Let $\vec{a}=\left(\begin{array}{c}0\\ 0\\1 \end{array} \right)$ Let $C_3 = \left( \begin{array}{ccc} c & -s & 0 \\ s & c & 0\\ 0 & 0 & 1 \end{array} \right)$ With s=sin(120 deg) and c= cos(120 deg). Calculate $\vec{b} = C_3 \vec{a}$ and $\vec{d} = C_3 \vec{b}$ Write d as linear combination of a and b. Show C_3^3 =1 and C_3 c = c with c=(0 0 1)