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aisha
#6
Nov30-04, 05:37 PM
P: 587
Thanks I get how to do it but want to make sure I did it right can you please check? Here is what I did:
(4x^2-9)-11(4x^2-9)+24=0
Let w=(4x^2-9)
w^2-11w+24=0
factored to become (w-8)(w-3)=0
sub in w value (4x^2-9-8)(4x^2-9-3)=0
(4x^2-17) (4x^2-12)=0

so solving for x
4x^2-17=0
4x^2=17
x=the square root of +or- 17/4

or 4x^2-12=0
4x^2=12
x=the square root of +or-3