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jbriggs444
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#4
Dec19-12, 01:41 PM
P: 751

Conservation of momentum/kinetic energy in inelastic collisions.


Quote Quote by Sweeney View Post
I'm finding it difficult to understand how momentum is conserved in an inelastic collision, but kinetic energy isn't. I understand some energy leaves the system in the form of sound and heat.

If we look at the momentum of the system before and after the collision, P=mV, they are equal, due to CoM. Assuming a constant mass we can also say that the velocity of the system is constant.
If there is a collision then there are at least three quantities that can be meant by "m" and at least three quantities that can be meant by "V".

It would seem that you are taking m to denote the sum of the masses of the colliding objects and V to denote the velocity of the center-of-mass of the colliding objects.

For momentum, that works out because P(total) = m(total) * V(average)

For energy, this does not work because E(total) != 1/2 m(total) * V(average)^2

Let's take an more familiar example... Suppose that you have a pile of building blocks. They are all shaped like cubes. Some are big and some are little. If you pile all the blocks on top of one another you can determine the height of the tower by multiplying the average size of each block by the number of blocks. But you cannot correctly determine the total volume of the blocks by taking the average size the blocks, cubing that and multiplying by the number of blocks.

The average of the cubes is not equal to the cube of the average.
The average of the squares is not equal to the square of the average.
The average of the inverse is not equal to the inverse of the average.

Averages don't commute in general.

That's why there are things like the "harmonic mean" or the "root mean square".