circular motion

regan1

how can rcosθ in a banked road be equal to mg; since r is equal to normal reaction which is equal to mgcosθ. rcos is even smaller than r.
so
mg>mgcosθ
mgcosθ=r
r>rcosθ
so
mg>rcosθ
then how can mg=rcos when banking in curved road?

regan1	circular motion Tweet how can rcosθ in a banked road be equal to mg; since r is equal to normal reaction which is equal to mgcosθ. rcos is even smaller than r. so mg>mgcosθ mgcosθ=r r>rcosθ so mg>rcosθ then how can mg=rcos when banking in curved road?