To extend on my point. At neutral, if you take position x along the beam, the distance of x from the mounting location is simply x.
However, if you take x at full deflection, according to the equation I posted above, it now has a position (x, y) or (x, w) in the case of that equation. Since x is the same, the new distance is going to be the magnitude of those, sqrt(x^2 + w^2). Therefore it is now further from the mounting position.