|
Hrm.
If a matrix A is diagonalizable, then I claim that there exists an n such that all of the nonzero eigenvalues of An lie in the right half-plane. The requirement that Tr(An) = 0, forces all the eigenvalues to be 0, and thus A is zero... clearly nilpotent!
So the trick, then, is when the matrix is not diagonalizable.
Then again, this only works for complex valued matrices.
|