Thread: 0^0 = 1?
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BenGoodchild
#25
May15-05, 04:24 PM
P: n/a
We cannot divide by 0.

Take the classic example:

a = b
a^2 = b^2
a^2 + a^2 = a^2 + ab
2(a^2) = a^2 + ab
2(a^2) - 2ab = 2(a^2) + ab - 2ab
2(a^2) - 2ab = 2(a^2) - ab
2((a^2) - ab) = 1((a^2) - ab)

then divide by (a^2) - ab) to give 1 =2

The fallacy comes right at the end when dividing by 0. So, we cannot divide by zero, and 0^0 is 0/0 therefore it is Mathematically undefined.

Regards,

M