 Quote by melissa_y
Ok so this is what I've done and I am not gettingthe problem right still....
I did T = 2pi (square root of L/g)
I took that T/2 = 5.5875
Then i set up this equation
5.5875/1.290 = 18/x
Then I solve for x and subtract the x from the theta given. I'm not sure what i"m doing wrong!
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The period calculation looks correct. Your last equation is not correct. Why are you not using the equation for theta from your original post?
theta= theta,o cos((2pi/T) t)