Thread: Modulus problem
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HallsofIvy
#2
Jul19-05, 09:08 AM
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Quote Quote by frozen7
( l 2-x l ^2 ) - 2 l 2-x l = 15

((2-x)^2) = 15 + 2 l 2-x l ------1
((2-x)^2) = -15 - 2 l 2-x l------2

Am I doing correctly?
How did you get 2?

I think that you intended to drop the absolute value signs.
Yes, |2-x|2l= (2-x)2. Either |2-x|= (2- x) (if 2-x>= 0) or |2-x|= -(2-x)

Change the absolute values to parentheses and you will correct.