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 Blog Entries: 9 Recognitions: Homework Help Science Advisor Use the Taylor expansions of the trig functions around 0 $$\sin x\simeq x-\frac{x^{3}}{3!}$$ $$\tan x\simeq x+\frac{x^{3}}{3}$$ It should come up to $-\frac{1}{2}$. Daniel.