View Single Post
 Quote by eljose the qeustion is that i have given a formula for $$\pi(x^a)$$ with error O(x^d) so let,s suppose we want to calculate $$\pi(10^{1000})$$ then set a=1000 and x=10 so the total error would be O(10^d) that is the advantage of my method.... if you want to judge the formula by yourselves it is: