Quote by Laceylb
well i think because there are two different answers for x and when you plug it back in you would have 6 total numbers, im just taking a guess as that

I see, but that makes it confusing for me. That's why i don't understand what to do.
Quote by GregA
Richay...try to identify the range of numbers that the solution definitely *isn't*.
For example...say I let n+2 = 4...what is the product of 4 and 6?...what is the product of 2 and 3? ( since n+2 = 4, our third number...our first and second are n and n+1 )...
secondly can n be somewhere around +/ 10 million?...whereabouts does n lie?
Be aware that potentially the problem might be expressed in any of these ways:
6n = (n+1)(n+2)
6n = (n1)(n2)
6n(n2) = (n1)(n)
6n(n+2) = (n+1)(n)
Only two of these is any help, the other two will not...which two cannot help and why?
(By finding the range of numbers that your solution isnt, you should be able to solve it just by inspection and then you should try to justify your choices by choosing and solving the correct quadratics)

I'll take a shot at this.
6n = (n+1)(n+2)...soso?? I can see that this problem can be figured out, but I can't find the correct numbers... HELP ME. Omg, i can't find a number that will fit in with all the problems. I think n is around 8 in this one. But i can't figure it out.
6n = (n1)(n2)...Works. Because:
6 x 2 = 12 (3) x (4) = 12. (Lacey showed me this solution eariler)
6n(n2) = (n1)(n) This can't possibly work. You can always prove me wrong though if you like. But you will never even get a close answer because the first equation will have a HIGH total. And the second equation will always be lower. SO, screw this one for now.
6n(n+2) = (n+1)(n) Screw this one too.
Well, that's as far as i got. What do i need to do next to progress?