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Position of a particle... 
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#1
Apr707, 09:53 PM

P: 16

1. The problem statement, all variables and given/known data
The position of a particle is given by the function x = ( 8t^3  3t^2 + 5) m, where t is in s. (a) At what time or times does vx = 0 m/s? (b) What are the particle's position and acceleration at t1? What are the particle's position and acceleration at t2? 2. Relevant equations v1 = v0 + at x1 = x0 + v0 + (1/2)at^2 vx = dx/dt a = dv/dt 3. The attempt at a solution Quite honestly, I'm not sure where to begin with this problem. If someone could help me to start it that would be greatly appreciated, thanks! 


#2
Apr707, 10:10 PM

HW Helper
P: 1,539

You know that v = dx/dt, and a = dv/dt. So for starters, take the derivatives.



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