Position of a particle...

by spin360
Tags: particle, position
 P: 16 1. The problem statement, all variables and given/known data The position of a particle is given by the function x = ( 8t^3 - 3t^2 + 5) m, where t is in s. (a) At what time or times does vx = 0 m/s? (b) What are the particle's position and acceleration at t1? What are the particle's position and acceleration at t2? 2. Relevant equations v1 = v0 + at x1 = x0 + v0 + (1/2)at^2 vx = dx/dt a = dv/dt 3. The attempt at a solution Quite honestly, I'm not sure where to begin with this problem. If someone could help me to start it that would be greatly appreciated, thanks!
 HW Helper P: 1,539 You know that v = dx/dt, and a = dv/dt. So for starters, take the derivatives.
HW Helper
P: 860
 Quote by spin360 [b]1. v1 = v0 + at x1 = x0 + v0 + (1/2)at^2

these are equation for constant acceleration. for your case acceleration is time dependent so can't use these

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