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Position of a particle...

by spin360
Tags: particle, position
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spin360
#1
Apr7-07, 09:53 PM
P: 16
1. The problem statement, all variables and given/known data
The position of a particle is given by the function x = ( 8t^3 - 3t^2 + 5) m, where t is in s.
(a) At what time or times does vx = 0 m/s?

(b) What are the particle's position and acceleration at t1?

What are the particle's position and acceleration at t2?

2. Relevant equations
v1 = v0 + at
x1 = x0 + v0 + (1/2)at^2
vx = dx/dt
a = dv/dt


3. The attempt at a solution
Quite honestly, I'm not sure where to begin with this problem. If someone could help me to start it that would be greatly appreciated, thanks!
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hage567
#2
Apr7-07, 10:10 PM
HW Helper
P: 1,542
You know that v = dx/dt, and a = dv/dt. So for starters, take the derivatives.
mjsd
#3
Apr7-07, 10:56 PM
HW Helper
mjsd's Avatar
P: 858
Quote Quote by spin360 View Post
[b]1.
v1 = v0 + at
x1 = x0 + v0 + (1/2)at^2

these are equation for constant acceleration. for your case acceleration is time dependent so can't use these


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