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Describing the distribution of n random variables |
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| Apr13-07, 02:16 PM | #1 |
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Describing the distribution of n random variables
Suppose I had n random variables, all of which have the same distribution but different mean and variances. How can I formally describe the distribution of these n random variables.
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| Apr13-07, 03:57 PM | #2 |
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If they have different means and variances, then they can't have the same distribution.
If you have n random variables all on the same set of outcomes S, then you describe that as a single random variable with outcomes in S^n. (the set of n-tuples of elements of S) And knowing the (marginal) distributions of the individual variables isn't enough: they could be dependent on each other in many different ways. |
| Apr15-07, 06:40 AM | #3 |
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So for example, if I had n normally distributed random variables, and each had different mean and variance, how do I describe the distribution of the n random variables. I just need to find out what the overall mean and variance of the n random variables will be?
Would this distribution be known as a joint distribution? Would I be able to use the multivariate normal distribution?? |
| Apr15-07, 10:31 AM | #4 |
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Describing the distribution of n random variables |
| Apr15-07, 04:40 PM | #5 |
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Thanks for help, Hurkyl.
So, is there any general formula or method for getting the joint distribution of n random variables. For example, if all the random variables were exponential (and I knew all the dependencies of the n random variables), is there a method?? There only seems to be multivariate normal and binomial distributions?? |
| Apr15-07, 05:30 PM | #6 |
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Suppose you have two random variables, each of which can take one of three outcomes. Their joint distribution can be described by a 3x3 array of numbers -- each entry is simply the probability of that particular joint outcome. Code:
0.05 0.20 0.10 | 0.35 0.15 0.05 0.05 | 0.25 0.10 0.15 0.15 | 0.40 -----------------+----- 0.30 0.40 0.30 | 1.00 Now, the question you appear to be asking is: Code:
* * * | 0.35 * * * | 0.25 * * * | 0.40 -----------------+----- 0.30 0.40 0.30 | 1.00 And the answer is no -- if you play around with it, you should be able to find many other joint distributions that yield this same diagram. |
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