Home school Calculas( high school level)


by Stupid_neko
Tags: calculas, home, school
Stupid_neko
Stupid_neko is offline
#1
May6-07, 05:18 PM
P: 3
Hi.. New at this site, hope I'm posting these stuff on the write place....
well i had these question below for review for an exam, hope someone can help me solve them, i did my solution in Paint program and on paper and am linking where i uploaded them, ( image shack)

-Find the second derivative
1)y=2x^3e^4x
solution


2)y=√(x^3+e^-x+5)
** for where 'e^-x' i think the question is wrong,, i think it should be e^x, not sure??
solution


3)Find the second derivative of 'y' with respect to "x" where
y=x^2/X^2
solution


4)Find the equation of 2 lines, each of slope 5, that are tangent to y=x^3+2X

5) Find the asymptotes for
f(x)=x/√(4x-1)

6)A dragster accelerates down a strip adn then brakes, adn comes to stop. Its position function, s(t) is given by s(t)=3t^2-1/5t^3, s'(t) in meters, 't' in seconds
a) when does the dragster come to a stop
b) how far has the dragster traveled.
Solution


7) Find the polynomial with second degree that goes through (1,-1) and whose slope is 1, When x=-1 and where slop is 19, when x=2
solution



8) A helicopter takes off from landing pad at 10:48AM and travels south at 150KM/h is planning to land at 10:56AM.
a) how far is the distance between them changing at 10:50AM( to 2 decimal place)
b) Is the distance between them increasing or decreasing at this instant?


I couldn't answer 4,5,8... please help me with them...and check solution
thank you ...
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turdferguson
turdferguson is offline
#2
May6-07, 07:41 PM
P: 312
For #4, the derivative is a quadratic. There are 2 places where the tan line has a slope of 5. Find the points where it equals 5 (or where that minus 5 equals zero) and then you have 2 points and 2 slopes
Noober
Noober is offline
#3
May6-07, 08:21 PM
P: 23
8. If he's traveling at 150 km/h, then that's how fast the distance is changing. For b, it depends. If it went past his destination before 10:50, then the distance is increasing, otherwise it's decreasing.

Stupid_neko
Stupid_neko is offline
#4
May6-07, 10:23 PM
P: 3

Home school Calculas( high school level)


Quote Quote by turdferguson View Post
For #4, the derivative is a quadratic. There are 2 places where the tan line has a slope of 5. Find the points where it equals 5 (or where that minus 5 equals zero) and then you have 2 points and 2 slopes
For quadratic equation i would need a,b and c. but i have only 2 numbers......and how would i find the point where the point equals 5?


Also can anyone check the solutions i did,

thanks
HallsofIvy
HallsofIvy is offline
#5
May7-07, 05:40 AM
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Thanks
PF Gold
P: 38,881
"For quadratic equation i would need a,b and c. but i have only 2 numbers......and how would i find the point where the point equals 5? "
A "point" can't equal 5! You are looking for the value of x such that the derivative 3x2+ 2= 5. Surely you can solve that equation.
sstone
sstone is offline
#6
May7-07, 07:38 AM
P: 14
For #1 the final answer(first derivative) is [tex](e^{4x} \cdot 2x^2) \cdot (4x+3)[/tex] not 2x + 3...you multiplyed by 2 insted 4...

Edit...even more simple it is if you leave it like this [tex]6x^2 e^{4x} + 8x^3 e^{4x}[/tex] and make a second derivative...
Stupid_neko
Stupid_neko is offline
#7
May7-07, 10:42 PM
P: 3
Quote Quote by sstone View Post
Edit...even more simple it is if you leave it like this [tex]6x^2 e^{4x} + 8x^3 e^{4x}[/tex] and make a second derivative...
I factored out the 2x^2, if you factor it back in , you get the same result....So confused,,,dont know where i made mistake sorry sorry,,,,,,,could you show me where i made the mistake,,,

thank you everyone for your help:)
sstone
sstone is offline
#8
May10-07, 10:24 AM
P: 14
You multiplied it wrongly...


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