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Outer differentiation? 
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#1
Feb1904, 10:08 AM

P: 559

Since I didn't get a response on the "Diff. Eqns." thread, I put it here.
Can someone give me a clear explaination of what is meant by "outer" differentiation. As for example, when we differentiate the vector potential, dA/dx, in order to arrive at the magnetic field, B, why would this be called an 'outer' differentiation?? [?] 


#2
Feb1904, 10:03 PM

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#3
Feb2004, 10:07 AM

P: 559

Thanks for the response, Turin;
and thanks for the correction. Oc course, you are accurate in saying it is the cross product of the gradient. I guess then if someone says "dA/dt is the outer differentiation" I should interpret that to mean they are simply referring to it as being a cross product.?? 


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