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A group G has exactly 8 elements or order 3 |
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| Jan30-08, 02:54 PM | #1 |
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A group G has exactly 8 elements or order 3
How many subgroups of order 3 does G have?
So we have 8 elements, its prime decomposition is 8=2^3. The number of different ways to get factors is how many subgroups, at least that is what I interpret from my notes...so there are 2^3, 2*2^2, and 2*2*2, so three different ways to get factors, am I doing this right? Thanks |
| Jan30-08, 05:00 PM | #2 |
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Do you mean G has 8 elements OR order 3, or do you mean G has 8 elements OF order 3.
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| Jan30-08, 05:16 PM | #3 |
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| Jan31-08, 02:06 AM | #4 |
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Recognitions:
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A group G has exactly 8 elements or order 3
every subgroup of order three has how many elements of order three?
and how many common elements of order three do two distinct subgroups of order three have? |
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