
#1
Jan3008, 02:54 PM

P: 15

How many subgroups of order 3 does G have?
So we have 8 elements, its prime decomposition is 8=2^3. The number of different ways to get factors is how many subgroups, at least that is what I interpret from my notes...so there are 2^3, 2*2^2, and 2*2*2, so three different ways to get factors, am I doing this right? Thanks 



#2
Jan3008, 05:00 PM

P: 1,076

Do you mean G has 8 elements OR order 3, or do you mean G has 8 elements OF order 3.




#3
Jan3008, 05:16 PM

P: 15




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