Car A vs Car B 0-100mph Race: Who Wins?

  • Context: High School 
  • Thread starter Thread starter Matty T
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SUMMARY

In a 0-100mph race, Car A outperforms Car B, finishing 11 meters ahead when both reach 100mph. Car A accelerates from 0-60mph in 4.3 seconds and from 60-100mph in 7.3 seconds, covering a total distance of 318.6 meters. In contrast, Car B accelerates from 0-60mph in 4.8 seconds and from 60-100mph in 6.8 seconds, covering 307.6 meters in total. The analysis utilizes the formula V_f^2 = V_0^2 + 2ax to determine distances and times.

PREREQUISITES
  • Understanding of kinematic equations, specifically V_f^2 = V_0^2 + 2ax
  • Knowledge of acceleration and its calculation using a = (V_f - V_0) / t
  • Familiarity with basic physics concepts related to motion and distance
  • Ability to interpret and analyze performance metrics of vehicles
NEXT STEPS
  • Explore advanced kinematic equations for varying acceleration scenarios
  • Research vehicle performance metrics and their impact on racing outcomes
  • Learn about the physics of acceleration and deceleration in automotive contexts
  • Investigate real-world racing simulations and their methodologies
USEFUL FOR

Automotive enthusiasts, race engineers, physics students, and anyone interested in vehicle performance analysis and racing dynamics.

Matty T
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car A & car B do 0-60mph in 4.3secs & 4.8secs respectively.
both do 0-100mph in 11.6secs

?in a straight line race from standstill which car would be in front & by how much when they hit 100mph?
 
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Are we to assume that the acceleration from 0 to 60 mph is constant, and that the acceleration from 60 mph to 100 mph is constant (but different)?

Anyway, you can solve this problem with one formula:
[tex]V_f^2 = V_0^2 + 2ax[/tex]
[tex]a = \frac{V_f - V_0}{t}[/tex]
[tex]x = \frac{V_f^2 - V_0^2}{2\frac{V_f - V_0}{t}} = \frac{t}{2}(V_f + V_0)[/tex]

Part 1: When the cars hit 60mph, car A will be at 57.6 meters and car B will be at 64.4 meters.
Part 2: Car A's acceleration from 60 to 100 takes 7.3 seconds, whereas car B's takes only 6.8 seconds. The distance car A will pass between 60mph and 100mph is 261 meters, whereas car B will only pass 243.2 meters.

The total distance of car A is 318.6 meters, and the total distance of car B is 307.6. So car A will be in front of car B by 11 meters when they both hit 100 mph.

Of course, I'm not sure I'm right and I'm probably not. :smile:
 

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