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How can an vehicle move faster than the wind that is powering it? |
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| Oct22-08, 12:27 PM | #171 |
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How can an vehicle move faster than the wind that is powering it?Same or different -- can't say as I wasn't referencing your comments. JB |
| Oct22-08, 01:29 PM | #172 |
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I absolutely love the "still air relative to the moon" bit. If I'm picking a frame of reference for sailing -- that's the one I'm using every single time. And hey, if the wind is still, relative to the moon, we'll only need a one foot mast and a hankerchief -- saves a lot of room down below.
This "physics" forum is a real kick. JB |
| Oct22-08, 01:29 PM | #173 |
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Someone made a comment about how diagrams are so "second degree university" - but there hardly seems to be 3 people here that understand the most basic high school physics concept of inertial reference frames. Discussing the prop-cart going downwind faster than the wind is beyond hopeless.
Heck, we've presented every possible type of evidence of what ice-boats are capable of - and all that has resulted in is silence. |
| Oct22-08, 01:48 PM | #174 |
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I wonder why.....let me know when you are ready to discuss the cart
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| Oct22-08, 02:35 PM | #175 |
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Recognitions:
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[QUOTE=Jeff Reid;1923648]Assuming the formula stated for a device with a Beta of 14 degrees, I made a graph of Vmg/Vt versus heading offset from true down wind. It peaks at about 2.56 at 38 degrees. http://jeffareid.net/misc/dwvhdg.gif[quote]I missed the obvious flaw that when the heading is 0 degrees offset from the wind direction, Vmg/Vt is 1.0, where it would have to be less than 1.0 because of drag. The Beta factor needs to vary based on heading.
Does anyone have an actual table of heading versus Vmg? Another issue is lift versus drag as it applies to sails. When heading downwind, aerodyamicd and ground lift are zero while aerodyanmic drag = ground drag. Also unlike wings, sails aren't designed to divert the air flow by 90 degrees. I need to do a rethink on this. |
| Oct22-08, 03:05 PM | #176 |
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