## dissipation, resistance, and power.

1. The problem statement, all variables and given/known data
A string of 19 identical Christmas tree lights
are connected in series to a 120 V source. The
string dissipates 60 W.
What is the equivalent resistance of the
light string? Answer in units of ohms.
What is the resistance of a single light? An-
swer in units of .

What power is dissipated in a single light?

One of the bulbs burns out. The lamp has a
wire that shorts out the bulb filament when it
burns out, dropping the resistance of the bulb
to zero.
What is the resistance Rnew of the light
string now? Answer in units of ohms.

Find the power Pnew dissipated by the string
now. Answer in units of W.

2. Relevant equations
P=IV
I=V/R
P=(V/R)V
R=V2/R

3. The attempt at a solution
I'm not sure how to start, since the dissipation of power is in watts. thanks for any hints or help you can give !
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Recognitions:
Homework Help
 Quote by exohemmx3 I'm not sure how to start, since the dissipation of power is in watts. thanks for any hints or help you can give !
Welcome to PF.

Well you have Power dissipated, and you have the Voltage don't you?

Can't you figure the resistance of the 19 bulbs together?

And if then the 19 become 18 what happens if figure power again from the same formula?

 Tags dissipation, ohms law, power, resistance, volts

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