# Coulomb's Law, net electrostatic force

by nn3568
Tags: coulomb, electrostatic, force
 P: 14 1. The problem statement, all variables and given/known data A particle with charge −9 μC is located on the x-axis at the point 8 cm, and a second particle with charge 5 μC is placed on the x-axis at 6 cm. The Coulomb constant is 8.9875 × 109 N · m2/C2. What is the magnitude of the total electrostatic force on a third particle with charge 2 μC placed on the x-axis at −2 cm? Answer in units of N. 2. Relevant equations Coulomb's Law fe = (kq1q2)/(d2) 3. The attempt at a solution (8.9875e9 * 2e-6 * 5e-6) / (0.08^2) = 14.04296875 (8.9875e9 * 5e-6 * -9e-6) / (0.02^2) = -983.0078125 14.04296875 + -983.0078125 = -997.0507813 magnitude 997.0507813 Why is this wrong? What can I do to make it right?
Mentor
P: 40,240
 Quote by nn3568 (8.9875e9 * 5e-6 * -9e-6) / (0.02^2) = -983.0078125
You want the force on the 2μC charge.
 P: 14 Thank you so much!

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