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electromagnetic forces

 
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Aug28-09, 04:42 PM   #1
 

electromagnetic forces


Speed = distance/time and current = charge/time. Explain how F=BIl is actually the same equation as F= Bqv but considered for many charges in a group?

can someone please explain with working out please?

thanks
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Aug28-09, 05:46 PM   #2
 
Lets say that you had a wire with a length l. Lets say that traveling through that length is a net charge q, with an average velocity of v. v = distance/time, in which in this case, v = l/t. The current is I = charge/time = q/t. Therefore, F = B*q*(l/t) = B*(q/t)*l = BIl.
Aug30-09, 06:13 AM   #3
 
thanks a lot!
Aug31-09, 03:08 PM   #4
 

electromagnetic forces


For clarity, these two equations (part of the Lorentz Force Law) are written as

F = l(I x B) = q(v x B)

where x indicates the cross product. meaning that the vectors F,I and B; or F,v,and B are all mutually orthogonal.
Aug31-09, 09:56 PM   #5
 
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The I/v vectors need not be orthogonal with the B vector.
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