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electromagnetic forces |
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| Aug28-09, 04:42 PM | #1 |
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electromagnetic forces
Speed = distance/time and current = charge/time. Explain how F=BIl is actually the same equation as F= Bqv but considered for many charges in a group?
can someone please explain with working out please? thanks |
| Aug28-09, 05:46 PM | #2 |
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Lets say that you had a wire with a length l. Lets say that traveling through that length is a net charge q, with an average velocity of v. v = distance/time, in which in this case, v = l/t. The current is I = charge/time = q/t. Therefore, F = B*q*(l/t) = B*(q/t)*l = BIl.
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| Aug30-09, 06:13 AM | #3 |
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thanks a lot!
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| Aug31-09, 03:08 PM | #4 |
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electromagnetic forces
For clarity, these two equations (part of the Lorentz Force Law) are written as
F = l(I x B) = q(v x B) where x indicates the cross product. meaning that the vectors F,I and B; or F,v,and B are all mutually orthogonal. |
| Aug31-09, 09:56 PM | #5 |
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The I/v vectors need not be orthogonal with the B vector.
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