
#1
Sep2709, 04:34 PM

P: 1

1. The problem statement, all variables and given/known data
A photographer in a helicopter ascending vertically at a constant rate of 12.5 m/s accidentally drops a camera out the window when the helicopter is 60.0 m above the ground. How long will it take the camera to reach the ground? What will its speed be when it hits? a= 9.8 m/s^2 displacement=60 m 2. Relevant equations (final v)^2=(initial v)^2 + 2*a*deltax deltax=1/2a(t^2)+(initial v*t) 3. The attempt at a solution initial v=0 so time will equal 3.5 s, and final velocity will equal 33.67 m/s^2 however, these are incorrect 



#2
Sep2709, 04:45 PM

Sci Advisor
HW Helper
P: 4,301

The initial v is not 0, but the v of the helicopter and photographer. If you don't believe is, look up some movies of a ball shot from a moving car: when the car is moving at 50 km/h and the ball is shot backwards at 50 km/h, it drops straight down.



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