New prime series?

suyver

No: this is indeed a function that generates all the primes. But it is a function with 26 parameters that can vary.... Computationally very intensive!

Sariaht

Originally posted by suyver

You mean that the answer of my question is: No?

How can you get all primes through this?

Or did you mean that his function generates all primes?

I'm comfused...

Good night!

suyver

In that other thread that I linked to, there is (about halfway through) a short discussion about this monster. That is a set that yields every prime number, as well as that it only yields prime numbers. However, there is one catch: you have to restrict its domain to parameters that give positive values (i.e. ignore all results <0).

I suggest that you spend some time reading that other thread. There is also a rough proof of the fact that it is fundamentally impossible to construct a nonconstant polynomial in a single variable over the integers that will generate all primes...

Sariaht

Does the x number of factors to form the n first numbers follow a maclaurin serie?

1 | 1f
2 | 2f
3 | 3f
4 | 5f
5 | 6f
6 | 8f etc.

You must agree in that it's a good question anyway...

geraldmcgarvey

"A multiple between two primes is always right in the middle of two primes."

Has that been proven, that the product of two primes is always the average of two primes?

Are all numbers > 2 the average of two primes?