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razorg425
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Hi guys just a quick question on how I would go about showing the units of Z21 is isomorphic toC2*C6(cyclic groups).I have done out the multiplicative table but they seem to be different to me. What else can I do?
An isomorphic group is a mathematical concept in abstract algebra where two groups have the same structure and are essentially the same, despite having different elements. In other words, isomorphic groups are groups that are equivalent to each other.
The group Z21, also known as the cyclic group of order 21, is a mathematical group consisting of integers modulo 21 under addition. This means that the elements of the group are the integers from 0 to 20, and the group operation is addition modulo 21.
The group C2*C6, also known as the direct product of C2 and C6, is a mathematical group formed by taking the Cartesian product of the cyclic group of order 2 (C2) and the cyclic group of order 6 (C6). This group contains elements of the form (a, b) where a belongs to C2 and b belongs to C6, and the group operation is defined as (a1, b1) * (a2, b2) = (a1 * a2, b1 * b2).
Yes, Z21 and C2*C6 are isomorphic groups. This is because both groups have the same number of elements (21), and they also have the same structure (cyclic groups of order 21). Therefore, they are essentially the same group, just with different elements.
We can prove that Z21 and C2*C6 are isomorphic by finding a bijective homomorphism between the two groups. In other words, we need to find a function that maps each element of Z21 to an element of C2*C6 in a way that preserves the group operation. Once we establish this function, we can show that it is both one-to-one and onto, proving that the two groups are isomorphic.