|Jan3-10, 05:07 PM||#1|
Science Fair, pressure to break a bone
1. The problem statement, all variables and given/known data
Okay, basically I had a bone in ballistic gels, and I dropped a hexagon (6 sided) weight with the measurements of 1 and 1/2 inches per side from 1 feet, 1 1/2 feet and 2 feet on the ballistic gel enclosed bone. Basically I will need a formula to calculate the psi that he bone experienced.
Edit: I calculated the area of the weight to be 13 1/2 square inches, but please double check this.
According to http://hyperphysics.phy-astr.gsu.edu/hbase/flobi.html , the N (Newton?) is 1599, can we convert it to PSI?
2. Relevant equations
How much PSI did the dropping weight cause on the bone?
3. The attempt at a solution
I tried to find a formula to calculate it, but was not really sucessful.
Edit: Okay, so the surface area is 13.5 square inches.. i do not know what formular to use to calculate PSI from this point.
|Jan3-10, 11:10 PM||#2|
You can't calculate it. If the bone is stiff and doesn't bend a lot, it would exert a huge force; if it does bend a lot, it would exert a small force. You really need to have something push down on the bone with its weight rather than dropping something and hoping to calculate pressure that way.
|Jan4-10, 02:23 AM||#3|
pounds x 4.4 = Newtons
1599/4.4 = pounds
Pounds/Area(in^2) = psi
|formula, height, psi, weight|
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