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A Hard integral

by kelvin911
Tags: integral
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kelvin911
#1
Feb1-10, 06:29 PM
P: 2
[tex]
\int_0^{\pi} \frac{x}{1+\sin(x)\cos(x)} dx
[/tex]
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kelvin911
#2
Feb1-10, 06:35 PM
P: 2
how does latex in this forum works???? how to get rid of the 18416 ?????

testing

[tex]\frac{1}{2}[/tex]

[tex]\int_0^{\pi} \frac{x}{1+\sin(x)\cos(x)} dx[/tex]
cronxeh
#3
Feb1-10, 06:42 PM
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P: 1,236
Why is this a hard integral? Post your work please

Prathyush
#4
Feb4-10, 11:16 AM
P: 61
A Hard integral

what is the method used?
cronxeh
#5
Feb4-10, 06:50 PM
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This is not a competition. I had the answer the minute I looked at the problem to make sure it existed. The point is to teach him how to find the solution by looking at his attempt at the solution. Please dont randomly post an answer which does not help him in any way.


To OP: for what its worth, sin(2*x) = 2*sin(x)*cos(x). You can try u=2*x, du = 2 dx
berkeman
#6
Feb4-10, 06:57 PM
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Quote Quote by cronxeh View Post
This is not a competition. I had the answer the minute I looked at the problem to make sure it existed. The point is to teach him how to find the solution by looking at his attempt at the solution. Please dont randomly post an answer which does not help him in any way.
Exactly. I've deleted the posts with answers in them. This is most likely homework, so giving the OP the answer is cheating. I'm moving this thread to Homework Help, Calculus and Beyond.


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