# Limits- using L'hopital's rule

by Jenkz
Tags: lhopital, limits, rule
 P: 1,395 You must have made an error while differentiating, the limit is not 0. [tan (x^1/2)]^2 is not the same as tanx. Try $x = \pi$
 P: 59 @Mark44: okies, noted. I've tried differentiating it again and I get: $$\frac{\frac{sec^{2}\sqrt{x}}{2\sqrt{x}}}{\sqrt{\frac{1}{x}+1}-\frac{1}{2\sqrt{\frac{1}{x}+x}}}$$ But it still doesn't give me a limit. I'm not too sure how to use your hint. As if i let $$\pi=x$$ Doesnt it just mean $$\pi$$ tends towards 0 instead of x ? Confused...