
#1
Dec1610, 05:27 AM

P: 2

Assuming atoms pack together as hard spheres , find the largest intenstihal atom that can fit in a BCC arrangement of iron atoms . Take the radius of the irom atoms as 1,21 Å . Carry out the same calculations for an FCC arrangment of iron atoms . On the basis of these caluclation would you expect carbon with an atomc radius of 0,77Å to occur as an intenstihal in BCC iron ? or FCC iron?




#2
Dec1610, 09:16 AM

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#3
Dec2110, 07:33 PM

P: 2

This is my solve
I) for BCC : assumming 2 unitcells : a= ( 4r )\[tex]\sqrt{}3[/tex] =2.86 A a) for the plane ( 0 1 0 ) ( the plane between the 2 cubics ) the free lenght between each 2 oppiste atoms = a[tex]\sqrt{}2[/tex]  2r = 1.56 A b) the free length between the 2 central atoms = a  2r = 0.38 A from a , b the largest radius = 0.38 A II) for FCC : assumming unitcell : a = 2a [tex]\sqrt{}2[/tex] =3.507 A the free space between each 2 oppiste face central atoms = a  2r = 1.0272 A the largest radius = 1.0272 A III) If I have carbon with r = 0.77 A it's possible to occur as an intastitial in a FCC May I have ur comments ??!! 


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