Register to reply

Partial F/ Partial T... F= (x,y) x and y = functs of s and t...Only step 1 needed

Share this thread:
Mar21-11, 07:45 PM
P: 6
Wrong area sorry. Nub here! Can someone delete this.

If f(x,y) = Sqrt[x^4 + y] and x = s^2 + t^2 + 1 and y = t^2 +t*Cos(2s)

How do i find

Partial f
Partial t

I made the tree diagram how f depends on x and y, which both depend on s and t.... so on my test I said it was

(Partials of all of these)

f/x*x/s*x/t + f/y*y/s*y/t

Looking back now I wonder why I put the s's in there, seems like I don't need them. (this was from a recent test and we get to redo 1 problem). My new idea is

f/x*x/t + f/x*x/y ? That seems to simple though

Can someone here point in the right direction?

Phys.Org News Partner Science news on
Experts defend operational earthquake forecasting, counter critiques
EU urged to convert TV frequencies to mobile broadband
Sierra Nevada freshwater runoff could drop 26 percent by 2100
Some Pig
Mar23-11, 06:04 AM
P: 38
[tex]\frac{\partial f}{\partial t}=\frac{\partial f}{\partial x}\frac{\partial x}{\partial t}+\frac{\partial f}{\partial y}\frac{\partial y}{\partial t}[/tex]

Register to reply

Related Discussions
Measuring effect size in regressio: std coefficients, partial r2, partial correlation Set Theory, Logic, Probability, Statistics 0
Mixed Partial and non-partial derivative definition General Physics 1
Angle of Incidence with partial reflection and partial refraction Introductory Physics Homework 5
Partial differential: partial scalar partial vector Differential Equations 3
Partial Fraction help needed Calculus & Beyond Homework 5