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Please help :( -Capacitors in series and parallel |
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| Jun28-11, 09:04 PM | #1 |
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Please help :( -Capacitors in series and parallel
1. The problem statement, all variables and given/known data
Find the relationship between C and C1 to make C equivalent= C The diagram is as shown below:- Code:
C1
A---------------------------||----
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=C1 = C
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B---------------------------------
C parallel= C1 + C2 + C3...... 1/C series= 1/C1 + 1/C2 + 1/C3 3. The attempt at a solution So on the right most of the diagram, C1 and C are in series, hence their combined capacitor is C1(C)/C1+C. And since the combined capacitor is in parallel with the other C1, C equivalent is C1(C)/C1+C + C1 = C However, I can't seem to solve that particular equation by making C as the subject.... Please help.. The answer provided by the textbook is: C=C1 (1+ square root of 5) / 2 Thanks... |
| Jun28-11, 09:07 PM | #2 |
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I guess my diagram is messed up even though i tried to fixed it, but yeah,
C1 is in series with C and those two combined are in parallel with C1..... |
| Jun29-11, 03:25 PM | #3 |
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Recognitions:
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Let's see some of the mathematical steps you've taken to try to solve for C.
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| algebra, capacitors, circuits |
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