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Paradox for the existence of 4,5 and 7 using Brocard's problem |
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| Jul6-11, 08:16 AM | #1 |
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Paradox for the existence of 4,5 and 7 using Brocard's problem
I have attatched my Paradox for the existence of 4,5 and 7 using Brocard's problem . I don't know where i have gone wrong as 4,5,7 exist, surely.
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| Jul6-11, 09:52 AM | #2 |
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On the second page you get [itex]\alpha\cdot sin(\alpha\pi)\Gamma(\alpha) + 1 = x^{2}[/itex] and that is not correct since [itex]sin(\alpha\pi)[/itex] are canceling eachother. The correct result is
[itex]\alpha\Gamma(\alpha) + 1 = x^{2}[/itex] |
| Jul12-11, 03:16 AM | #3 |
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Using Euler's reflection formula its correct.
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| Jul12-11, 03:31 AM | #4 |
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Paradox for the existence of 4,5 and 7 using Brocard's problem
Yup, but you apply it twice and therefore the result should have been without the sin(α*pi)
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